Evaluating Functions
In this lesson, we will learn how to evaluate functions. Evaluating a function involves substituting a value into the function and computing the result. This is a fundamental skill in algebra that helps in understanding how functions work.
Outline
- Understanding Function Notation
- Substituting Values into Functions
- Example Problems
- Practice Exercises
- Homework
- Revision
Examples
Example 1
Given the function f(x) = 2x + 3
, find f(4)
.
Solution: Substitute x = 4
into the function:
f(4) = 2(4) + 3 = 8 + 3 = 11
Example 2
Given the function g(x) = x^2 - 5x + 6
, find g(2)
.
Solution: Substitute x = 2
into the function:
g(2) = 2^2 - 5(2) + 6 = 4 - 10 + 6 = 0
Example 3
Given h(x) = \frac{1}{x + 1}
, find h(-2)
.
Solution: Substitute x = -2
into the function:
h(-2) = \frac{1}{-2 + 1} = \frac{1}{-1} = -1
Example 4
Given f(x) = 3x^2 - 2x + 1
, find f(0)
.
Solution: Substitute x = 0
into the function:
f(0) = 3(0)^2 - 2(0) + 1 = 0 - 0 + 1 = 1
Example 5
Given g(x) = 2x - \frac{3}{x}
, find g(1)
.
Solution: Substitute x = 1
into the function:
g(1) = 2(1) - \frac{3}{1} = 2 - 3 = -1
Example 6
Given h(x) = \sqrt{x + 4}
, find h(5)
.
Solution: Substitute x = 5
into the function:
h(5) = \sqrt{5 + 4} = \sqrt{9} = 3
Exercises
1. Evaluate f(x) = x^3 - 2x
for x = -1
.
Solution: f(-1) = (-1)^3 - 2(-1) = -1 + 2 = 1
2. Evaluate g(x) = 4x + 7
for x = 3
.
Solution: g(3) = 4(3) + 7 = 12 + 7 = 19
3. Evaluate h(x) = \frac{2x}{x - 1}
for x = 2
.
Solution: h(2) = \frac{2(2)}{2 - 1} = \frac{4}{1} = 4
4. Evaluate f(x) = 5 - x^2
for x = -3
.
Solution: f(-3) = 5 - (-3)^2 = 5 - 9 = -4
5. Evaluate g(x) = \sqrt{2x + 3}
for x = 4
.
Solution: g(4) = \sqrt{2(4) + 3} = \sqrt{8 + 3} = \sqrt{11}
6. Evaluate h(x) = \frac{x^2 - 1}{x + 1}
for x = 0
.
Solution: h(0) = \frac{0^2 - 1}{0 + 1} = \frac{-1}{1} = -1
Homework
1. Evaluate f(x) = 2x^2 - 3x + 4
for x = 5
.
2. Evaluate g(x) = \frac{3x + 2}{x - 4}
for x = 6
.
3. Evaluate h(x) = \sqrt{x^2 + 1}
for x = -2
.
4. Evaluate f(x) = x^3 - 4x
for x = 1
.
5. Evaluate g(x) = 7 - \frac{x}{2}
for x = 8
.
6. Evaluate h(x) = \frac{x + 1}{x - 2}
for x = 3
.
Revision
To review what we have learned about evaluating functions:
- Function notation represents a function as
f(x)>, where
x
is the input variable. - To evaluate a function, substitute the given value into the function and simplify.
- Be careful with different types of functions such as linear, quadratic, and rational functions when substituting values.
- Practice various functions to strengthen your understanding of how to handle different function types and operations.
Video Explanation
Watch the following video for a comprehensive explanation of evaluating functions:
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