Function Notation, Algebra I

Function Notation - Algebra I

Understanding Function Notation

Description: In this lesson, we will explore function notation, a key concept in Algebra I. Function notation provides a concise way to represent functions and their outputs. You will learn how to read and use function notation to solve problems.

Outline

  • Introduction to Function Notation
  • Examples of Function Notation
  • Exercises and Solutions
  • Homework
  • Revision

Introduction to Function Notation

Function notation is used to represent functions in a compact way. If f(x) is a function, f is the name of the function and x is the input value. The function f(x) gives the output when x is substituted into the function.

Examples of Function Notation

Example 1:

Given the function f(x) = 2x + 3, find f(4).

Solution: Substitute x = 4 into the function:

f(4) = 2(4) + 3 = 8 + 3 = 11

Example 2:

For the function g(x) = x² - 5, calculate g(-2).

Solution: Substitute x = -2 into the function:

g(-2) = (-2)² - 5 = 4 - 5 = -1

Example 3:

Consider the function h(x) = 3x - 7. What is h(0)?

Solution: Substitute x = 0 into the function:

h(0) = 3(0) - 7 = -7

Example 4:

Find the output of the function f(x) = -x + 9 when x = 6.

Solution: Substitute x = 6 into the function:

f(6) = -6 + 9 = 3

Example 5:

Given p(x) = 4x - 1, determine p(3).

Solution: Substitute x = 3 into the function:

p(3) = 4(3) - 1 = 12 - 1 = 11

Example 6:

For the function q(x) = x/2 + 5, find q(8).

Solution: Substitute x = 8 into the function:

q(8) = 8/2 + 5 = 4 + 5 = 9

Exercises

Exercise 1:

Find f(5) if f(x) = x² + 2x.

Solution: Substitute x = 5:

f(5) = 5² + 2(5) = 25 + 10 = 35

Exercise 2:

Calculate g(-1) for g(x) = -3x + 4.

Solution: Substitute x = -1:

g(-1) = -3(-1) + 4 = 3 + 4 = 7

Exercise 3:

Determine h(2) if h(x) = 2x + 6.

Solution: Substitute x = 2:

h(2) = 2(2) + 6 = 4 + 6 = 10

Exercise 4:

What is f(-3) for f(x) = -x + 8?

Solution: Substitute x = -3:

f(-3) = -(-3) + 8 = 3 + 8 = 11

Exercise 5:

Find p(4) if p(x) = 3x - 7.

Solution: Substitute x = 4:

p(4) = 3(4) - 7 = 12 - 7 = 5

Exercise 6:

Determine q(0) for q(x) = x/3 + 2.

Solution: Substitute x = 0:

q(0) = 0/3 + 2 = 0 + 2 = 2

Exercise 7:

Given r(x) = 5x - 2, find r(-4).

Solution: Substitute x = -4:

r(-4) = 5(-4) - 2 = -20 - 2 = -22

Exercise 8:

Calculate s(6) for s(x) = x² + 3x.

Solution: Substitute x = 6:

s(6) = 6² + 3(6) = 36 + 18 = 54

Exercise 9:

What is t(-2) if t(x) = -2x + 5?

Solution: Substitute x = -2:

t(-2) = -2(-2) + 5 = 4 + 5 = 9

Exercise 10:

Find u(1) for u(x) = 7 - x.

Solution: Substitute x = 1:

u(1) = 7 - 1 = 6

Homework

  • Complete Exercises 1-10 from the examples and practice problems provided.
  • Create 5 additional functions and solve for different values of x.
  • Write a brief explanation of why function notation is useful in algebra.

Revision

Review the following points to solidify your understanding of function notation:

  • Function notation uses the format f(x) to represent functions and their outputs.
  • Substitute the input value x into the function to find the output.
  • Practice interpreting and solving function notation problems to gain confidence.

Learn More

Watch this video for a detailed explanation of function notation: Function Notation Explained

If you have any questions or need further assistance, contact us for online tutoring at Luna Learn 24, or text us to book a tutor. Follow us on Facebook and YouTube for more educational content!

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